Indian Wells: a Swiss opponent in singles

Indian Wells: a Swiss opponent in singles

06/03/2018 – Belinda Bencic is 70th in the world rankings.


The main draw was made for singles at the 8 648 508 USD BNP Paribas Open: Timi’s opponent will be Belinda Bencic.


The Hungarian player is 43rd in the world rankings.

Bencic (born: 7 March, 1997) is 70th and her career best position was 7th (22 February, 2016). So far she has won 2 WTA Tour, 2 WTA125 and 4 ITF tournaments in singles. In the 2014 season, she was quarter-finalist at the US Open, this is her best result at a Grand Slam event.


This year, she won the Hopman Cup on Roger Federer’s side, with 3 wins (Coco Vandeweghe, Anastasia Pavlyuchenkova and Naomi Osaka) and 1 defeat (Angelique Kerber). At the Australian Open, she won 6:3, 7:5 against Venus Williams, then lost 6:1, 6:3 against from Luksika Kumkhum. In the Fed Cup, she lost twice against the Czech Republic and she lost in the opening round in Acapulco.

The Hungarian and Swiss player have met twice: at the 2016 Australian Open Bencic won 6:3, 6:3, and a few months later in Cincinnati, Timi won 7:5, 6:2.